Xethtine
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| Wed Dec 05, 2007 7:22 pm Physics invoved with moving a suitcase (for Wes) |
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Ok, Wes, after this, you'll never be able to look at a suitcase the same ever again...
a=0
m=18kg
fk=27N
FP=43
angle (@) = ?
Ok, so now we add a freebody diagram...
So, we need to find the angle that the handle makes witht the suitcase.
sin@ = 33.47/43 inverse sin, algebra stuff....
anyway, @ = 51.1 degrees
Now, we need to find FN (normal force) of the suitcase
Use a sum of forces equation (mg is negative because it goes down)
The sum is 0 bcecause a (acceleration) = 0 and ΣF = ma so if a = 0 then ma = 0 hence ΣF = 0
g (acceleration due to gravity) = 9.8 on earth (and for all purposes, we are moving this suitcase on earth)
ΣF= FN + 43sin51.1 - mg = 0
FN = mg - 43sin51.1
FN = (18 x 9.8 ) - 43sin51.1
FN = 142.94 N
Ok, only one more thing...
the soefficient of friction (μk)
fk = μk x FN
27 = μk x 142.94
27/142.94 = μk
μk = .19
Well, there you go. The physics (most of it anyway) involved with moving a suitcase. :) |
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